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select replace(分类名称,'传染病报告卡2016-','') 分类名称,
选项名称,
关键值 from (
select Replace(a.select_idnex_name,'传染病报告卡2016—','') 分类名称,
b.ITEM_DISPLAYNAME 选项名称,
b.ITEM_key_value 关键值
from DELIT_SELECTITEM_INDEX a, DELIT_SELECT_ITEMS b
where a.ID = b.SELECTID
and SELECT_IDNEX_NAME like '传染病报告卡2016%')
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